Answer:
![A= 2\pi (3cm)^2 +1 2\pi (3cm)(10 cm)= 18 \pi + 60\pi = 78 \pi cm^2](https://img.qammunity.org/2021/formulas/mathematics/high-school/lgfc749p9uu973my8aqn0au2ck7ukncn8m.png)
And replacing the value of
we got:
![A = 78*3.14 cm^2= 244.92 cm^2](https://img.qammunity.org/2021/formulas/mathematics/high-school/em85i0st2xcl4at6wfb933bsless2wj7gm.png)
Explanation:
For this case we have the long who represent the height 10 cm and the diameter is 6cm. So then the radius is given by:
![r = (D)/(2)= (6cm)/(2)= 3cm](https://img.qammunity.org/2021/formulas/mathematics/high-school/l7ygkuo1y4vax56xkv58rmauqai33ueu5m.png)
And the surface area for a cylinder is given by this formula:
![A= 2\pi r^2 +2 \pi rh](https://img.qammunity.org/2021/formulas/mathematics/high-school/27n18i8j39uvqcw7bu1bktnepl2kd3hq9p.png)
And replacing the info given we got:
![A= 2\pi (3cm)^2 +1 2\pi (3cm)(10 cm)= 18 \pi + 60\pi = 78 \pi cm^2](https://img.qammunity.org/2021/formulas/mathematics/high-school/lgfc749p9uu973my8aqn0au2ck7ukncn8m.png)
And replacing the value of
we got:
![A = 78*3.14 cm^2= 244.92 cm^2](https://img.qammunity.org/2021/formulas/mathematics/high-school/em85i0st2xcl4at6wfb933bsless2wj7gm.png)