Answer:
NaNO3
Step-by-step explanation:
Hello,
In this case, the required reaction is an acid-base neutralization reaction which is said to be:

There, we see that the sodium displaced the hydrogen in the nitric acid to form sodium nitrate a very used salt in the industry, so, as a result of that displacement, water is formed as the secondary neutralization product. For the above mentioned, answer is NaNO3 .
Best regards.