Answer:
7/10
Step-by-step explanation:
Given the following set of numbers: {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}
There are 5 even outcomes: {2, 4, 6, 8, 10}
There are 3 multiples of 3: {3, 6, 9}.
Combining these lists we get 7 desired outcomes: {2, 3, 4, 6, 8, 9, 10}
Therefore, the probability of drawing an even number or a multiple of 3 is: (desired outcomes)/(total outcomes) = 7/10