Question

John runs 1.0 m/s at first, and then accelerates to 1.6 m/s during

the course of 4.5 seconds. What is his average acceleration (in
m/s2

Answer 1

Answer:.13

Step-by-step explanation:

Answer 2

Answer:
`0.13m/s^2`

Step-by-step explanation:

`Formula: a=(V_2-V_1)/(t)`

Where;

a = acceleration

V2 = final velocity

V1 = initial velocity

t = time

If John runs 1.0 m/s first, we assume this is V1. He accelerates to 1.6 m/s; this is V2.

`a=(1.6m/s-1.0m/s)/(4.5s)`

`a=(0.6m/s)/(4.5s)`

`a=0.13m/s^2`