Answer:
The probability that exactly half of the colonies will thrive = (1/3) = 0.3333
Explanation:
The list of random numbers simulates the out comes of 4 colonies.
Based On the simulation in 6 trails, what is the probability that exactly half of the colonies will thrive?
The probability of an event is given mathematically as the number of elements in the event divided the total number of elements in the sample space.
Noting that the numbers 0 to 6 indicate that a colony thrives and the number 7 to 9 represent that a colony doesn't thrive.
The 6 trials are given as
4285; 3 colonies thrive, 1 doesn't.
6903; 3 colonies thrive, 1 doesn't.
3829; 2 colonies thrive, 2 don't.
7871; 1 colony thrives, 3 don't.
2868; 2 colonies thrive, 2 don't.
5137; 3 colonies thrive, 1 doesn't.
The number of trials where exactly 2 colonies thrive = 2
The total number of trials = 6
The probability that exactly half of the colonies will thrive = (2/6) = (1/3) = 0.3333
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