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Triangle A B C is shown. Angle A B C is 95 degrees and angle B C A is 45 degrees. The length of A B is c and the length of B C is 3.0 centimeters. Law of sines: StartFraction sine (uppercase A) Over a EndFraction = StartFraction sine (uppercase B) Over b EndFraction = StartFraction sine (uppercase C) Over c EndFraction Which represents the value of c? C = StartFraction (3) sine (40 degrees) Over sine (45 degrees) EndFraction c = StartFraction (3) sine (45 degrees) Over sine (40 degrees) EndFraction c = StartFraction sine (40 degrees) Over (3) sine (45 degrees) EndFraction c = StartFraction sine (45 degrees) Over (3) sine (40 degrees)

User Odalys
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2 Answers

1 vote

Answer:

B

Explanation:

User Mashea
by
7.6k points
2 votes

Answer:

(B)c = StartFraction (3) sine (45 degrees) Over sine (40 degrees) EndFraction


c=(3 * \sin 45)/(sin 40)

Explanation:

In Triangle ABC is shown.


\angle A B C= 95 degrees


\angle B C A = 45 degrees.

|AB|=c

|BC|=3.0 cm


\angle A+\angle B+\angle C=180^\circ\\\angle A+95+45=180\\\angle A=180-140=40^\circ

Using the Law of Sines


(a)/(\sin A)=(b)/(\sin B)=(c)/(\sin C)


(3)/(\sin 40)=(c)/(\sin 45)\\\\$Cross multiply\\c*\sin 40 =3 * \sin 45\\\\c=(3 * \sin 45)/(sin 40)

The correct option is B.

User Rozsazoltan
by
8.8k points
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