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Solve dy/dx = (1-x)(1-y)

User Shabana
by
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1 Answer

3 votes

Answer:


y=1-e^{c_(2)}}*e^(-x) *e^(x^2)

Explanation:

We begin with the differential equation
(dy)/(dx) =(1-x)(1-y)

Firstly, we need to get the
y and
dy as well as the
x and
dx on the same sides as each other

To do this, we can multiply each side by
dx and divide each side by
(1-y)

Doing this will give us the following differential


(1)/(1-y) dy=(1-x)dx

Now, we can integrate each side


\int\limits(1)/(1-y) \, dy =\int (1-x) \, dx\\\\-ln(1-y)=x-x^2+c_(1)

Now, we need to solve for y


-ln(1-y)=x-x^2+c_(1)\\\\ln(1-y)=x^2-x+c_(2) \\\\1-y=e^{x^2-x+c_(2)} \\\\y=1-e^{x^2-x+c_(2)}\\\\y=1-e^{c_(2)}}*e^(-x) *e^(x^2)

User Achiash
by
4.6k points