Question

Find two consecutive integers such that the smaller integer decreased by nine equals three times the larger integer.

Answer 1

Let the first integer be x, since they are consecutive, the other will be x + 1

Following the question;

x-9 = 3(x + 1)

x -9 = 3x + 3

3x-x = -3-9

2x = -12

x = -12/2

x = -6 and x + 1 = -6 + 1 = -5

The integers are -6 and -5