Question

Solve 4r-3/6r+1 = 2r-1/3r+4​

Answer 1

r = 1

Explanation:

Given

`(4r-3)/(6r+1)` =
`(2r-1)/(3r+4)` ( cross- multiply )

(6r + 1)(2r - 1) = (3r + 4)(4r - 3)

Expand factors on both sides using FOIL

12r² - 4r - 1 = 12r² + 7r - 12 ( subtract 12r² from both sides )

- 4r - 1 = 7r - 12 ( subtract 7r from both sides )

- 11r - 1 = - 12 ( add 1 to both sides )

- 11r = - 11 ( divide both sides by - 11 )

r = 1