Answer: A circle of radius 2 around the point (4, - 5)
Explanation:
I guess the equations are:
X = 2*cos(t) + 4
Y = 2*sin(t) - 5
Let's try some values and see where we get from that:
If t = 0°
X = 2 + 4 = 6
Y = 0 - 5 = -5
if t = 90°
X = 0 + 4
Y = 2 - 5 = -3
If t = 180°
X = - 2 + 4 = -2
Y = 0 - 5 = - 5
if t = 270°
X = 0 + 4 = 4
Y = -2 - 5 = -7
Now, if you graph those points you will see that we are creating a circle of radius 2 around the point (4, -5)
Actually, always when we have a equation:
X = R*cin(x) + a
Y = R*sin(x) + b
the graph will be a circle of radius R around the point (a,b)