Answer:
A. 1.5A.
B. 3V
C. 4.5V
D. 1.5V
E. 9V
Step-by-step explanation:
A. Determination of the current in the circuit.
We'll begin by calculating the total resistance. This is illustrated below:
R1 = 2Ω
R2 = 3Ω
R3 = 1Ω
Total resistance (RT) =..?
RT = R1 + R2 + R3
RT = 2 + 3 + 1
RT = 6Ω
Therefore, the total resistance is 6Ω.
Now, we can obtain the current in the circuit as follow:
Voltage(V) = 9V
Total Resistance (R) = 6Ω
Current (I) =..?
V = IR
I = V /R
I = 9/6
I = 1.5A
Therefore, the current in the circuit is
B. Determination of the voltage across 2Ω resistor.
Resistor (R) = 2Ω
Current (I) = 1.5A
Voltage (V) =..?
V = IR
V = 1.5 x 2
V = 3V.
Therefore, the voltage across 2Ω resistor is 3V.
C. Determination of the voltage across 3Ω resistor.
Resistor (R) = 3Ω
Current (I) = 1.5A
Voltage (V) =..?
V = IR
V = 1.5 x 3
V = 4.5V.
Therefore, the voltage across 3Ω resistor is 4.5V.
D. Determination of the voltage across 1Ω resistor.
Resistor (R) = 1Ω
Current (I) = 1.5A
Voltage (V) =..?
V = IR
V = 1.5 x 1
V = 1.5V.
Therefore, the voltage across Ω resistor is 1.5V.
E. Determination of the sum of the voltage across all three resistor.
Voltage across 2Ω (V1) = 3V
Voltage across 3Ω (V2) = 4.5V
Voltage across 1 (V3) = 1.5V
Total voltage (VT) =..?
VT = V1 + V2 + V3
VT = 3 + 4.5 + 1.5
VT = 9V
Therefore, the sum of the voltage across all three resistor is 9V.