Answer:
A. 3Ω.
B. 2A.
C. 2V.
D. 4V.
Step-by-step explanation:
A. Determination of the total resistance.
Resistance 1 (R1) = 1Ω
Resistance 2 (R2) = 2Ω
Total resistance (RT) =..?
Since the resistance are in series connection, the total resistance can be obtained by adding both resistance as shown below:
RT = R1 + R2
RT = 1 + 2
RT = 3Ω
Therefore, the total resistance is 3Ω
B. Determination of the current in the circuit.
Voltage (V) = 6V
Total resistance (R) = 3Ω
Current (I) =..?
V = IR
I = V /R
I = 6/3
I = 2A.
Therefore, the current flowing in the circuit is 2A.
C. Determination of the voltage across 1Ω resistance.
Resistance (R) = 1Ω
Current (I) = 2A
Voltage (V) =..?
V = IR
V = 2 x 1
V = 2V.
Therefore, the voltage across 1Ω resistance is 2V.
D. Determination of the voltage across 2Ω resistance.
Resistance (R) = 2Ω
Current (I) = 2A
Voltage (V) =..?
V = IR
V = 2 x 2
V = 4V.
Therefore, the voltage across 2Ω resistance is 4V.