Answer:
Explanation:
Assume the dimensions of the castle are as in the diagram below.
There are four structures to consider:
- A rectangular prism
- A rectangular pyramid
- A cylinder
- A cone
1. Number of heaters
The total volume will have to be heated for the comfort of the guests.
(a) Volume of cylinder
d = 16 ft, so
r = 8 ft
V = πr²h = π × (8 ft)² × 60 ft = 12 063 ft³
(b) Volume of cone
V = ⅓πr²h = ⅓π × (8 ft)² × 15 ft = 1005 ft³
(c) Volume of rectangular prism
V = lwh = 198 ft × 42 ft × 60 ft = 498 960 ft³
(d) Volume of rectangular pyramid
(i) Height of pyramid
AC² + BC² = AB²
AC² + (99 ft)² =(101 ft)²
AC² + 9801 ft² =10 201 ft²
AC² = 400 ft²
h = AC = 20 ft
(ii) Volume of pyramid
V = ⅓Bh = ⅓ × 198 ft × 42 ft × 20 ft = 55 440 ft³
(e) Total volume
V = 12 064 ft³ + 1005 ft³ + 498 960 ft³ +55 440 ft³ = 567 469 ft³
(f) Number of heaters
2. Amount of plaster
Only the vertical surfaces of the castle must be plastered. The roofs are probably of slate.
We need to consider only the lateral surface areas of the rectangular prism and the cylinder.
(a) Lateral area of rectangular prism
LA = 2lh +2wh = 2 × 198 ft × 60 ft + 2 × 42 ft × 60 ft = 23 760 ft² + 5040 ft² = 28 800 ft²
(b) Lateral area of cylinder
LA = 2πrh = 2π × 8 ft × 60 ft = 3016 ft²
(c) Amount of plaster
Plaster = 28 800 ft² + 3016 ft ² = 31 816 ft²