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10) Intravenous saline solutions have a concentration of 1.5 M NaCl. How many liters of saline can be prepared from 50.0 g of NaCl?

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Answer:

0.57 mol/L

Step-by-step explanation:

Molarity (M) is defined as the number of moles of solute per liter of solution (moles/Liter).

Molarity =
(moles of solute)/(liters of solution) or Moles = molarity × litres

so, the mass of Nacl in 1 mol is 58.44 g,

Moles of NaCl = 50.0g x 1 mole NaCl / 58.44 g

= 0.855 mol NaCl

Moles = molarity × litres

0.855 = 1.5 M x L

L = 0.57 mol/L

Hence, 0.57 mol/L can be prepared from 50.0 g of NaCl.

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