Question

Consider the total ionic equation below.

Ba2+ + 2NO3 + 2Na+ + Co3 —BaCO3 + 2Na+ + 2NO3

Which is the net ionic equation for the reaction?

O Ba2+ + C03 —> BaCO3

© 2Na+ + co} → Na2CO3

NO3 + Na* —> NaNO3

O Ba2+ + 2NO3 →→ Ba(NO3)2

Answer 1

Complete Question

Consider the total ionic equation below.

`Ba^(2+) + 2NaO_3^(1 -) + 2Na^(+) + CO_3^(2-) ----> BaCO_3 + 2Na^(+) + 2NO_3^(1-)`

Which is the net ionic equation for the reaction?

A
`Ba^(2+) _((aq)) + CO_3 ^(2-) _((aq)) ----> BaCO_3_((s))`

B
`2Na^+ + CO_2 ----> Na2CO3`

C
`NO3 + Na ^ + ----> NaNO3`

D
`Ba_2^+ + 2NO3 ----> Ba(NO3)2`

Answer:

Option A is the correct option

Step-by-step explanation:

The given ionic equation is

`Ba^(2+) + 2NaO_3^(1 -) + 2Na^(+) + CO_3^(2-) ----> BaCO_3 + 2Na^(+) + 2NO_3^(1-)`

Looking at this complete ionic equation we see that
`Na^(+1) \ and \ NO_3^(1-)` did not change in the reaction so they will not be included in the net ionic equation so the net ionic equation becomes

`Ba^(2+) _((aq)) + CO_3 ^(2-) _((aq)) ----> BaCO_3_((s))`

Answer 2

Ba²⁺ + CO₃²⁻ → BaCO₃

Step-by-step explanation:

A net ionic equation is a way to write a chemical reaction in which you list only the species that are participating in the reaction.

For the reaction:

Ba²⁺ + 2NO₃ + 2Na⁺ + CO₃²⁻ → BaCO₃ + 2Na⁺ + 2NO₃

As you can see, NO₃ and Na⁺ are not participating in the reaction. Thus, net ionic equaation is:

Ba²⁺ + CO₃²⁻ → BaCO₃