Question

Create a series circuit with a 10-volt battery and four 10-ohm resistors, as shown. Measure the current. A. Based on the voltage and current, what is the resistance of the circuit? (Hint: Use Ohm’s law.)

Answer 1

See the attachment for circuit and position of ammeter in the circuit to measure the current.

40ohms

Step-by-step explanation:

Ammeter in always connected in series with other elements in the circuit.

Measured current= 0.25A

According to ohm's law

V=IR

10= (0.25) R

R= 40 ohms

Answer 2

0.25 A

Resistance= 40 ohms

Step-by-step explanation:

The first, and perhaps most important, the relationship between current, voltage, and resistance is called Ohm's Law, discovered by Georg Simon Ohm and published in his 1827 paper. Ohm's law states that the current through a conductor between two points is directly proportional to the voltage across the two points. Introducing the constant of proportionality, the resistance, one arrives at the usual V=IR. Any Electrical device or component that obeys “Ohms Law” that is, the current flowing through it is proportional to the voltage across it ( I α V ), such as resistors or cables, are said to be “Ohmic” in nature.

Since we are not in a laboratory, we can not experimentally measure the current but it can be calculated from ohm's law.

Given that the four resistors are connected in series and

Req= R1 + R2 + R3 + R4

Since all are four ohm resistors

Req= 10 + 10+10+10 = 40ohms

Then;

V= 10 V

R= 40ohms

I= ???

From;

V=IR

I= 10/40

I= 0.25 A