Question

A 2.00 L container of nitrogen had a pressure of 3.20 atm. What volume would be

necessary to decrease the pressure to 1.03 atm?

Answer 1

`\large \boxed{\text{6.21 L}}`

Step-by-step explanation:

The temperature and amount of gas are constant, so we can use Boyle’s Law.

`p_(1)V_(1) = p_(2)V_(2)`

Data:

`\begin{array}{rcrrcl}p_(1)& =& \text{3.20 atm}\qquad & V_(1) &= & \text{2.00 L} \\p_(2)& =& \text{1.03 atm}\qquad & V_(2) &= & ?\\\end{array}`

Calculation:

`\begin{array}{rcl}3.20 * 2.00 & =& 1.03V_(2)\\6.40 & = & 1.03V_(2)\\V_(2) & = &(6.40)/(1.03)\\\\& = &\textbf{6.21 L}\\\end{array}\\\text{The new volume must be } \large \boxed{\textbf{6.21 L}}`