Question

A 125 g sample of strontium was heated from 0°C to 20°C. It absorbed 750 J of energy. What is the specific heat capacity of iron?

Answer 1

Specific heat capacity of iron (C)
`= 0.3` J/g°C

Step-by-step explanation:

As we know that

Specific heat capacity of iron (C)
`=(\delta E)/( [m* \delta T])`

Where
`\delta E` represents the change in the energy

m represents the mass of the sample and

`\delta T` represents the change in temperature.

Given:

Mass of sample (m)
`= 125` gram

Change in heat (
`\delta T` )
`20 - 0 = 20`

Absorbed energy (
`\delta E`)
`= 750` J

Substituting the given values in above equation, we get -

Specific heat capacity of iron (C)

`= (750)/(125*20)`

Specific heat capacity of iron (C)
`= 0.3` J/g°C

Answer 2

Specific heat capacity of iron (C) = 0.3 J/GK

Step-by-step explanation:

Given:

Mass of sample (m) = 125 gram

Change in heat (ΔT) = 20°C - 0°C = 20°C

Absorbed energy (ΔE) = 750 J

Find:

Specific heat capacity of iron (C) = ?

Computation:

⇒ Specific heat capacity of iron (C) = ΔE / [mΔT]

⇒ Specific heat capacity of iron (C) = 750 / [125 × 20]

⇒ Specific heat capacity of iron (C) = 750 / [2,500]

⇒ Specific heat capacity of iron (C) = 0.3 J/GK