Question

The percent yield of a reaction in which 52 grams of a reactant is expected to yield 30 grams of product is 25%. What is the actual yield of the reaction? A) 13 grams B) 120 grams C) 208 grams D) 7.5 grams

Answer 1

D) 7.5 grams

Step-by-step explanation:

Hello,

In this case, since the percent yield is defined by:

`Y=(m^(actual))/(m^(theoretical)) *100\%`

In such a way, since the percent yield is up to 25% and the expected or theoretical amount is 30 g of the product, the actual yield of the reaction is:

`m^(actual)=(Y*m^(theoretical))/(100\%) =(25\%*30g)/(100\%) \\\\m^(actual)=7.5g`

Therefore the answer is D) 7.5 grams.

Best regards.