Answer:
For this case we know that the total distance to travel is 325 mi. And we know that Aretha travels at the following velocity:
![V = (X)/(t) = (195 mi)/(3 hr)= 65 (mi)/(hr)](https://img.qammunity.org/2021/formulas/mathematics/high-school/dvvu95hqasntm5ugwaudk4p218xazpnkrf.png)
Then we can use the following definition:
![D = Vt](https://img.qammunity.org/2021/formulas/physics/college/f4nfvtagmfb6375kf4cttqcf91uj33n827.png)
Where D is the distance and V the velocity. And solving for t we got:
![t = (D)/(V)](https://img.qammunity.org/2021/formulas/mathematics/high-school/nz02crisrrrpxa9zv7lirfd37ru612c0wb.png)
And replacing we got:
![t = (325 mi)/(65 (mi)/(hr))= 5](https://img.qammunity.org/2021/formulas/mathematics/high-school/d4ldenlvyrc9a5qisz32b3uccad6alhkgl.png)
So then we can conclude that after 5 hours at this rate Aretha will arrive to home
Explanation:
For this case we know that the total distance to travel is 325 mi. And we know that Aretha travels at the following velocity:
![V = (X)/(t) = (195 mi)/(3 hr)= 65 (mi)/(hr)](https://img.qammunity.org/2021/formulas/mathematics/high-school/dvvu95hqasntm5ugwaudk4p218xazpnkrf.png)
Then we can use the following definition:
![D = Vt](https://img.qammunity.org/2021/formulas/physics/college/f4nfvtagmfb6375kf4cttqcf91uj33n827.png)
Where D is the distance and V the velocity. And solving for t we got:
![t = (D)/(V)](https://img.qammunity.org/2021/formulas/mathematics/high-school/nz02crisrrrpxa9zv7lirfd37ru612c0wb.png)
And replacing we got:
![t = (325 mi)/(65 (mi)/(hr))= 5](https://img.qammunity.org/2021/formulas/mathematics/high-school/d4ldenlvyrc9a5qisz32b3uccad6alhkgl.png)
So then we can conclude that after 5 hours at this rate Aretha will arrive to home