Question

`3\sqrt[5]{(x+2)^3}+3=27`
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Answer 1

Explanation:

`3\sqrt[5]{(x+2)^(3)}+3=27`

`3\sqrt[5]{(x+2)^(3)}=27-3`

`ln 3\sqrt[5]{(x+2)^(3)}= ln 24`

`ln 3 + ln\sqrt[5]{(x+2)^(3)}= ln 3 + ln 8`

`ln\sqrt[5]{(x+2)^(3)}= ln 8`

`(3)/(5) ln(x+2)= ln 8`

`ln(x+2)=(5)/(3) ln 8`

x + 2 =
`\sqrt[3]{8^(5)}`

x =
`\sqrt[3]{8^(5)}` -2