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18.35 mL of an HCN solution were titrated with 35.4mL of a 0.268M NaOH solution to reach the equivalence point. What is the molarity of the HCN solution

User Shivanand
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2 Answers

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Answer: 0.517

Step-by-step explanation:

User Louis Thibault
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Answer:

0.517

Step-by-step explanation:

HCN + NaOH → NaCN + H2O [balanced as written]

(35.4 mL) x (0.268 M NaOH) x (1 mol HCN / 1 mol NaOH) / (18.35 mL HCN) = 0.517 M HCN

User Amin Mohammadi
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