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Find the limit of the function by using direct substitution lim (x^2+8x-2) x-> 2

User Hugo R
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1 Answer

2 votes

Answer:


lim_(x \to 2) x^2 +8x -2

And using the properties of limit we got:


lim_(x \to 2) x^2 +8 \lim_(x \to 2) x - lim_(x \to 2) 2

And replacing we got:


2^2 + 8 (2) -2 = 4 +16-2 =18

Explanation:

For this case we want to find this limit:


lim_(x \to 2) x^2 +8x -2

And using the properties of limit we got:


lim_(x \to 2) x^2 +8 \lim_(x \to 2) x - lim_(x \to 2) 2

And replacing we got:


2^2 + 8 (2) -2 = 4 +16-2 =18

User Ykatchou
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