Answer:
0.396M
Step-by-step explanation:
Step 1:
The balanced equation for the reaction. This is given below:
2HNO3 + Ba(OH)2 —> Ba(NO3)2 + 2H2O
From the balanced equation above,
The mole ratio of the acid (nA) = 2
The mole ratio of the base (nB) = 1
Step 2:
Data obtained from the question. This include the following:
Volume of base (Vb) = 0.05L
Concentration of base (Cb) =..?
Volume of acid (Va) = 0.072L
Concentration of acid = 0.55 M
Step 3:
Determination of the concentration of the base, Ba(OH)2.
The concentration of the base, Ba(OH)2 can be obtained as follow:
Cava /CbVb = nA/nB
0.55 x 0.072 / Cb x 0.05 = 2/1
Cross multiply to express in linear form
Cb x 0.05 x 2 = 0.55 x 0.072
Divide both side by 0.05 x 2
Cb = (0.55 x 0.072) / (0.05 x 2)
Cb = 0.396M
Therefore, the concentration of the base, Ba(OH)2 is 0.396M