Question

How much thermal energy does it take to raise the temperature of 4.5 kg of water from 12°C to 97° C? The specific heat of water is 1.68 kJ/(kg*^ C) Use Q=mg(T f^ - T i ) .

Answer 1

642.6 x 10³ J

Step-by-step explanation:

Q = ms(
`T_f-T_i` ) ; m is mass , s is specific heat and
`T_f-T_i` is rise in temperature .

Putting the given data in the equation we get as follows

Q = 4.5 x 1.68 x 10³ x ( 97 - 12 )

= 642.6 x 10³ J .