Question

How many ml of 0.225M HCl would be needed to titrate 6.00 g of KOH

Answer 1

`v=475mL` of HCl

Step-by-step explanation:

Hcl + KOH. -------> KCl + H2O

the number of moles of KOH. can be calculated by converting the mass to molar mass, then, the mass is divided by it's molecular weight I.e

n = m/M

n = 6.00g/56.106g/mol

n = 0.106940434 mol

n= 0.107 mols of HCl

To calculate the Concentration

C = n/v

where n = number of moles and v = volume

0.225M = (0.106940434 mol)/v

v = (0.106940434 mol)/(0.225M)

v = 0.475290818 L × 1000mL HCl

`v=475mL`