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How much paint is needed to paint the front of the house? Question 2 options: 324 ft2 276 ft2 336 ft2 264 ft2

User CactusCake
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1 Answer

3 votes

Answer:

We need to use at least 4 cans to paint the wall.

Explanation:

The complete question is attached.

The wall can be divided in two forms, a rectangle and a triangle. The base of the rectangle is 3 meters, and its height is 2 meters. The base of the triangle is 3 meters too, but its height is 1 meter.

Using the given information, we have


A=A_(rectangle) +A_(triangle)\\ A=(3m * 2m )+ ((1)/(2) * 3m * 1m)\\A=6 \ m^(2) + 1.5 \ m^(2)=7.5 \ m^(2)

The area of the wall is 7.5 square meters.

But, 1 can of paint can cover 24 square feet.

We know that 7.5 square meters are equal to 80.73 square feet. Then, we use the given relation between can of paint and the area they can cover


n=80.73\ ft^(2) * (1 \ can)/(24 \ ft^(2) ) \approx 3.4 \ cans

Therefore, we need to use at least 4 cans to paint the wall.

How much paint is needed to paint the front of the house? Question 2 options: 324 ft-example-1
User Timea
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7.2k points