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4 votes
Circle T is shown. Line segments P R and Q S are diameters. Lines are drawn to connect point P and point Q and point S and point R to form 2 triangles. Angle P Q T is 40 degrees. Line P R and Line Q S are diameters of circle T. What is the measure of Arc S R? 50° 80° 100° 120°

User Mcclosa
by
5.8k points

2 Answers

5 votes

Answer:

C

Explanation:

User Taudris
by
4.9k points
4 votes

Answer:

(C)100°

Explanation:

See attached diagram to understand the problem better.


|QT|=|PT|$ (radii of circle T)\\Therefore \triangle QPT $ is an isosceles triangle\\\angle PQT=\angle QPT=40^\circ$ (base angles of an isosceles triangle)


\angle PQT+\angle QPT+\angle PTQ=180^\circ$ (sum of angles in a \triangle )\\40^\circ+40^\circ+ \angle PTQ=180^\circ\\\angle PTQ=180^\circ-80^\circ\\\angle PTQ=100^\circ

The measure of arc SR=Central Angle STR


\angle PTQ=\angle STR $ (Vertically opposite angles)\\\angle STR=100^\circ\\mSR=100^\circ

Circle T is shown. Line segments P R and Q S are diameters. Lines are drawn to connect-example-1
User Garrett Berneche
by
5.6k points
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