32.4k views
5 votes
In ΔJKL, j = 180 inches, ∠J=134° and ∠K=7°. Find the length of k, to the nearest 10th of an inch.

User Bwitkowicz
by
4.4k points

1 Answer

4 votes

Answer:

30.5 inches

Explanation:

In ΔJKL,

j = 180 inches, ∠J=134°

∠K=7°, k=?

We determine the length of k using the Law of Sines.


(k)/(\sin K) =(j)/(\sin J) \\\\(k)/(\sin 7^\circ) =(180)/(\sin 134^\circ) \\$Cross multiply\\k*\sin 134^\circ=180*\sin 7^\circ\\$Divide both sides by \sin 134^\circ$ to obatin k.\\k=(180*\sin 7^\circ)/(\sin 134^\circ) \\\\k=30.5$ inch (to the nearest 10th of an inch)

The length of k is 30.5 inches (correct to the nearest 10th of an inch.)

User Willy Lazuardi
by
4.3k points