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H(x) = x2 + 3x – 18

Rewrite the function by completing the square

User LastElb
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1 Answer

2 votes

Answer:

h(x) = (x + 3/2)^2 - 81/4

Explanation:

h(x) = x^2 + 3x – 18 (note the required use of " ^ " to indicate exponentiation)

Here 3 is the coefficient of the x term. Take half of this 3 and square the result: (3/2)^2 = 9/4.

Going back to h(x) = x^2 + 3x – 18

Add 9/4 and then subtract 9/4:

h(x) = x^2 + 3x + 9/4 - 9/4 – 18

Rewrite this as h(x) = (x + 3/2)^2 - 9/4 - 18, or

h(x) = (x + 3/2)^2 - 81/4

User Korina
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