Question

The product of two consecutive positive integer is 306. We need to find the Integers.

Hope you guys are help me.​

Answer 1

Let the given set of integers be n and (n+1)

n(n+1)=306

n to the power square +n−306=0

(n+17)(n−16)=0

Therefore, n=16 and integers are 16 and 17.

Answer 2

17, 18

Step-by-step explanation:

Let the integers be y, y + 1

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• y * (y + 1) = 306 (products of them)

• y² + y = 306 (multiply)

• y² + y - 306 = 0

• y² + 18y - 17y -306 = 0 (factorize)

• y(y+18) -17(y+18) = 0 (take out common variables)

• (y-17)(y+18) = 0 (collect into groups)

• y = 17, -18

• y = 17 (as required positive integer)

Next integer:

• y + 1

• 17 + 1

• 18