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If α and β are zeroes of the polynomial q(x)=x2-7x+10, then find the value of (α+β)2-4αβ

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Answer:

9

Explanation:


\alpha + \beta = -b/a = -(-7)/1 = 7


\alpha \beta = c/a = 10/1 = 10


(\alpha + \beta )^2 - 4 \alpha \beta \\ 7^2 - 4 × 10 \\ 49 - 40 \\ = 9

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