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Factor completely: 45x3 + 123x + 104x + 28

А
(5x + 7)? (3x + 2)
B
150rº (5x + 7) (3x + 2)
с
(5x+7) (9x + 4)
D
(5x+7) (3x + 2)2

User Geckob
by
7.0k points

1 Answer

0 votes

Answer:

45x^3 + 123x^2 + 104x + 28

=(45x^3 + 60x^2 + 20x) + (63x^2 + 84x + 28)

=5x(9x^2 + 12x + 4) + 7(9x^2 + 12x + 4)

=(5x + 7)(9x^2 + 12x + 4)

=(5x + 7)(3x + 2)^2

=> Option D is correct

Hope this helps!

:)

User Jon Jaques
by
7.6k points