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What is the numbers of moles in 20.0g of NaOH
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What is the numbers of moles in 20.0g of NaOH

User Sarah West
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Answer:

The numbers of moles in 20.0g of NaOH:

n=
(m)/(M) =
(20.0)/(23+16+1)) =
(1)/(2) (moles)

User Obed Castillo
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