What is the numbers of moles in 20.0g of NaOH

asked Jan 17, 2021 89.2k views

1 vote

8.4k points

0 Comments

Please log in or register to add a comment.

0 votes

Answer:

The numbers of moles in 20.0g of NaOH:

n=
(m)/(M) =
(20.0)/(23+16+1)) =
(1)/(2) (moles)

Obed Castillo answered Jan 22, 2021

7.4k points

0 Comments

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers