Question

Problem A spring was at its resting position where it is attached to a wall at its left side and a block at its right side as shown below. The spring constant is k=95.5\,\dfrac{\text N}{\text m}k=95.5 m N ​ k, equals, 95, point, 5, start fraction, start text, N, end text, divided by, start text, m, end text, end fraction. The block is moved rightwards and the spring's right end is displaced from the position of 0.200\,\text m0.200m0, point, 200, start text, m, end text to 0.220\,\text m0.220m0, point, 220, start text, m, end text where it is held in place. All positions are measured from the origin OOO of the wall. What is the spring force exerted on the block?

Answer 1

Answer:-1.91

Step-by-step explanation:

Kahn academy approved

.220m-.200m= .020

-(95.5) (.020) =-1.91

Answer 2

F = 19.1 N

Step-by-step explanation:

To find the force exerted by the string on the block you use the following formula:

`F=kx` (1)

k: spring constant = 95.5 N/m

x: displacement of the block from its equilibrium position = 0.200 m

you replace the values of k and x in the equation (1):

`F=(95.5N/m)(0.200m)=19.1N`

Hence, the force exterted on the block is 19.1 N