Answer:
The rise in temperature is 0.064 ⁰C
Step-by-step explanation:
Given;
mass of loose bag of soil, m = 15.53 kg
height of fall, h = 5.50 m
Potential energy of the fall, U = mgh
U = 15.53 x 9.8 x 5.5
U = 837.067 J = 0.200 kCal
If all the potential energy of the fall is retained by the soil in the bag, then the potential energy of fall is equal to thermal energy of the soil.
U = Q = mcΔθ
where;
Q is quantity of heat retained by the soil in the bag
m is mass of the loose bag of soil
c is specific heat capacity of the soil = 0.200 kcal/kg ⁰C
Δθ is increase in temperature
Δθ = U / mc
Δθ = 0.2 / (15.53 x 0.2)
Δθ = 0.064 ⁰C
Therefore, the rise in temperature is 0.064 ⁰C