Answer:
v = 0.33 m/s
Step-by-step explanation:
The final velocity of the skier and boat can be calculated by conservation of the lineal momentum:
![m_(1)v_(1i) + m_(2)v_(2i) = m_(1)v_(1f) + m_(2)v_(2f)](https://img.qammunity.org/2021/formulas/physics/high-school/7yu1jipp4bvr9xj1qq58tj8i88lo1qa01h.png)
Where:
m1: is the mass of the water skier = 62.0 kg
m2: is the mass of the boat = 775 kg
v1i: is the initial velocity of the water skier = 4.50 m/s
v1f: is the final velocity of the water skier = ?
v2i: is the initial velocity of the boat = 0
v2f: is the final velocity of the boat = ?
Since the final velocity of the skier is the same that the final velocity of the boat, we have:
Therefore, the final velocity of the skier and boat is 0.33 m/s.
I hope it helps you!