Question

A chemist needs to neutralize 25.5 L of 3.86 M chloric acid (HClO3). What mass of sodium hydroxide is

needed to accomplish this?

Answer 1

3.94 × 10³ g

Step-by-step explanation:

Step 1: Write the neutralization reaction

HClO₃ + NaOH = NaClO₃ + H₂O

Step 2: Calculate the moles of chloric acid that react

25.5 L of 3.86 M chloric acid is to be neutralized. The reacting moles are:

`25.5L * (3.86mol)/(L) =98.4mol`

Step 3: Calculate the required moles of sodium hydroxide

The molar ratio of HClO₃ to NaOH is 1:1. Then, the reacting moles of NaOH are 98.4 moles.

Step 4: Calculate the mass of sodium hydroxide corresponding to 98.4 moles

The molar mass of NaOH is 40.00 g/mol.

`98.4mol * (40.00g)/(mol) =3.94 * 10^(3) g`