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What is the vertex of the graph of the function below?
y = x2 +10x + 24

User Jerry Ajay
by
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1 Answer

4 votes

Answer:


\huge\boxed{(-5,\ -1)}

Explanation:


\text{The vertex form of a quadratic equation}\ y=ax^2+bx+c:\\\\y=a(x-h)^2+k\\\\\text{where}\ (h,\ k)\ \text{is a vertex},\ \text{and}\ h=(-b)/(2a),\ k=f(h).


\text{We have}\ y=x^2+10x+24\to a=1,\ b=10,\ c=24.\\\\\text{Substitute:}\\\\h=(-10)/(2(1))=(-10)/(2)=-5\\\\k=f(-5)\to\text{put}\ x=-5\ \text{to the equation}:\\\\k=(-5)^2+10(-5)+24=25-50+24=-1\\\\\text{The vertex}:\ (-5,\ -1)

What is the vertex of the graph of the function below? y = x2 +10x + 24-example-1
User Dewey
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6.7k points