Question

3. Una cuerda de guitarra tiene 60 cm de longitud y una masa de 0.05 kg de masa. Si se tensiona mediante una fuerza de 20 N. La frecuencia del primer armónico o tono fundamental es

Answer 1

f1 = 12.90 Hz

Step-by-step explanation:

To calculate the first harmonic frequency you use the following formula for n = 1:

`f_n=(n)/(2L)\sqrt{(T)/(M/L)}`

`f_1=(1)/(2L)\sqrt{(T)/(M/L)}` ( 1 )

It is necessary that the unist are in meters, then you have:

L: length of the string = 60cm = 0.6m

M: mass of the string = 0.05kg

T: tension on the string = 20 N

you replace the values of L, M and T in the expression (1) for getting f1:

`f_1=(1)/(2(0.6m))\sqrt{(20N)/(0.05kg/0.6m)}=12.90\ Hz`

Hence, the first harmonic has a frequency of 12.90 Hz