Answer:
12.5%
Step-by-step explanation:
We must first determine the fraction of radium-226 remaining after 4860 years. We can obtain that from;
Nt/No = (1/2)^t/t1/2
Where;
Nt= amount of radium-226 remaining after time t
No= amount of radium-226 available at time t=0
t1/2 = half life of radium-226= 1620 years.
t= time taken for Nt amount of radium-226 to remain= 4860 years
Substituting values;
Nt/No = (1/2)^ 4860/1620
Nt/No = (1/2)^3
Nt/No = 1/8
The percentage of the original sample remaining after 4860 years= 1/8 ×100 = 12.5%
Hence 12.5% of radium-226 remains after 4860 years.