Question

A submarine dives at a constant speed of 10 m/s at a diving angle measured from the vertical

of 75º. If the submarine starts its dive from the surface, how deep is the front end of the
submarine at the end of a 1-minute dive?​

Answer 1

155.3 m

Explanation:

We have:

θ: is the angle measured from the vertical = 75 °

v = is the speed of the submarine = 10 m/s

t = 1 min

The deep of the front end of the submarine at the end of a 1-minute drive is given by the following ratio:

`cos (\theta) = (x)/(d)`

Where:

d: is the distance traveled by the submarine in 1 minute

x: is the deep to find

The distance, d, is:

`d = v*t = 10 (m)/(s)* 1 min * (60 s)/(1 min) = 600 m`

Now, the deep is:

`cos (75) = (x)/(600)`

`x = cos(75)*600 = 155.3 m`

Therefore, the deep of the front end of the submarine at the end of a 1-minute drive is 155.3 m.

I hope it helps you!