Question

Si se pesan 0.456 gramos de NaOH y se disuelven en 100.0 ml de solución. ¿cuál es la molaridad?

O 0.114 M.
O 0.134 M
0.001M
1.00 x 10-3 M​

Answer 1

`M=0.114M`

Step-by-step explanation:

Hello,

In this case, we define the molarity as the ratio between the moles of the solute, NaOH here, and the volume of the solution in litres:

`M=(n)/(V)`

For that reason, one must first compute the moles of sodium hydroxide by using its molar mass of 40 g/mol:

`n=(0.456g)/(40g/mol)=0.0114mol`

Then, the volume in litres:

`V=100.0mL*(1L)/(1000mL) =0.1000L`

Finally we compute the molarity:

`M=(0.0114mol)/(0.1000L)\\ \\M=0.114M`

Best regards.