Question

A 15 m long wire is placed horizontally on the surface of a liquid and is gently pulled up with a force of 60 to keep the wire in equilibrium. What is the surface tension of the liquid?

Answer 1

Step-by-step explanation:

From the question we are told that

The length of the wire is
`L = 15 \ m`

The force with which its pulled up is
`F = 60 \ N`

The surface tension of the liquid is mathematically represented as

`S = (F)/(2L)`

substituting values

`S = (60)/(2* 15)`

`S = 2 Nm^(-1)`