Question

A 2-kg wheel rolls down the road with a linear speed of 15m/s. Find its trwansitional and rotational kinetic energies.​

Answer 1

The translational kinetic energy is 225 J

The rotational kinetic energy is 225 J

Step-by-step explanation:

Given;

mass of the wheel, m = 2-kg

linear speed of the wheel, v = 15 m/s

Transnational kinetic energy is calculated as;

E = ¹/₂MV²

where;

M is mass of the moving object

V is the velocity of the object

E = ¹/₂ x 2 x (15)²

E = 225 J

Rotational kinetic energy is calculated as;

E = ¹/₂Iω²

where;

I is moment of inertia

ω is angular velocity

`E = (1)/(2) I \omega^2\\\\E = (1)/(2) *mr^2*((v)/(r))^2\\\\E = (1)/(2) *mr^2*(v^2)/(r^2) \\\\E = (1)/(2)mv^2`

E = ¹/₂ x 2 x (15)²

E = 225 J

Thus, the translational kinetic energy is equal to rotational kinetic energy