Question

A bag contains 4 blue and 6 green marbles. Two marbles are selected at random from the bag. If the first marble is NOT replaced before the second marble is drawn, what is the P(blue second | green first)?

Answer 1

I think it's 4/10

Explanation:

P(B|G) =p(BnG)/ p(G) =

P(4x6)/6 4x6=24.

24/6 = 4/10