Question

Suppose the number of dropped footballs for a wide receiver over the course of a season are normally distributed with a mean of 16 and a standard deviation of 2. What is the z score for a wide reciever who dropped 13 footballs over the course of a season ?

Answer 1

-1.5

Explanation:

Answer 2

The z score for a wide receiver who dropped 13 footballs over the course of a season

Z = - 1.5

Explanation:

Explanation:-

Given Population mean ' μ'= 16

Standard deviation of Population 'σ' = 2

Let 'x' be the Random Variable of Normal distribution

Given x = 13 foot balls

The z score for a wide receiver who dropped 13 footballs over the course of a season

`Z = (x-mean)/(S.D)`

`Z = (13 -16)/(2) = (-3)/(2) = -1.5`

Final answer:-

The z score for a wide receiver who dropped 13 footballs over the course of a season

Z = - 1.5