Answer:
339,292 cm³
Explanation:
Assume that each ball bearing is a perfect sphere and that no material is wasted during the production.
The volume of a sphere is:
![V=(4)/(3)\pi r^3](https://img.qammunity.org/2021/formulas/mathematics/high-school/u0r42x4x15iywcq2jjsgy68j0i36han18j.png)
If each ball bearing has a diameter of 6 cm (radius of 3 cm), the individual volume is:
![V=(4)/(3)\pi* 3^3\\V=113.097\ cm^3](https://img.qammunity.org/2021/formulas/mathematics/high-school/1j07zgf2oybrzotk8wiyllte0bvbfybv0i.png)
For 3,000 ball bearings:
![V_(3,000)=3,000*V\\V_(3,000)=3,000*113.097\\V_(3,000)=339,292\ cm^3](https://img.qammunity.org/2021/formulas/mathematics/high-school/maxb4s0cofchxf00xs3r42bczvo3jk2yro.png)
339,292 cm³ of metal are needed to make 3,000 ball bearings.