Question

7) Find x- intercepts

Answer 1

See below:

Explanation:

At x axis intercepts, the value of y = 0

0 = -3/5 ( x+7)^2 + 6

-6(-5/3) = (x+7)^2

10 = (x+7)^2

x = -7 +- sqrt (10)

Answer 2

`x = -7 \pm \sqrt{10`

Explanation:

The x-intercepts occur where y = 0.

-3/5(x + 7)² + 6 = 0

-3(x + 7)² + 30 = 0

-3(x² + 14x + 49) + 30 = 0

-3x² - 42x - 147 + 30 = 0

3x² + 42x + 117 = 0

`x = (-42 \pm √(42^2 - 4(3)(117)))/(2(3))`

`x = (-42 \pm √(360))/(6)`

`x = (-42 \pm 6√(10))/(6)`

`x = -7 \pm \sqrt{10`