Answer:
It will take the ball 1 or 2secs to reach height of 32ft
Explanation:
At maximum height, the final velocity of the object is zero. Using one of the equation of motion as shown;
S = ut + 1/2gt²
S is the height reached by the ball
U is the initial velocity
g is the acceleration due to gravity
t is the time taken by the ball to reach maximum height.
Since the object is kicked upward, g will be negative.
Given the following details
S = 32feet, U = 48ft/s g = -32ft/s
32 = 48t-1/2(32)t²
32 = 48t -16t²
16t²-48t+32 = 0
t² - 3t+2 = 0
t²-t-2t+2 = 0
t(t-1)-2(t-1) = 0
(t-1)(t-2) = 0
t = 1 or 2seconds